Logarithmic Exponential Equations

Solution:
log₃(2^x - 7) = 2
log₃(2^x - 7) = log₃3²
2^x – 7 = 3²
2^x – 7 = 9
2^x = 16
2^x = 2⁴
x = 4

K = {4}

Solution:

Solution:
log₃( 1 + log₃(2^x-7)) = 1
log₃( 1+ log₃(2^x-7)) = log₃3
1 + log₃(2^x-7) = 3
log₃(2^x-7) = 2
log₃(2^x-7) = log₃9
2^x-7 = 9
2^x = 16
2^x = 24
x = 4

K = {4}

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