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Two lines in a plane

1. Characterize the properties of two lines in a plane.

Solution:

Two lines p, q in a plane are:

a) distinct parallel
two-lines-1a
b) coincident parallel
two-lines-1b
c) intersecting
two-lines-1c

The intersection point P of two intersecting lines is determined by solving their system of equations.

The angle φ between two lines is determined as the angle between their direction (or normal) vectors, or using their slopes kp, kq
two-lines-1d

The distance d between two parallel lines is determined as the distance from a point (belonging to one line) to the other line.

The bisector of the angle between two intersecting lines is the line whose points are equidistant from both intersecting lines. (dp = dq)

2. Determine the mutual position of lines p and q, given:

two-lines-2
Solution:

two-lines-2r

Lines p, q are intersecting and meet at point P[3;2].

3. Determine the mutual position of lines p and q, given:

two-lines-3
Solution:

two-lines-3r

The lines are intersecting and meet at point P[1;-6].

4. The equations of the sides of triangle ΔABC are:

a: [x – y + 1 = 0]
b: [2x + 7y – 70 = 0]
c: [7x + 2y -20 = 0]

Calculate the vertices of this triangle.
Solution:

two-lines-4

The vertices of the triangle are A[0;10], B[2;6], and C[7;8].

5. Opposite sides of a square lie on parallel lines:

p: [5x - 12y - 65 = 0]
q: [5x - 12y + 26 = 0]

Determine the area of the square.
Solution:

two-lines-5

The side of the square is d = 7 units.

S = d2
S = 72
S = 49 u2

The area of the square is S = 49 u2.

6. Triangle ΔABC is defined by the sides:

a: [x + 3y – 7 = 0]
b: [x – y – 3 = 0]
c: [x – 2y + 3 = 0]

Determine:
a) the vertices of the triangle
b) the center and radius of the circumscribed circle of the triangle
Solution:

two-lines-6

7. For point M [1;2], find point N [x;y] symmetric with respect to line p:[x – y - 1 = 0].

Solution:

The desired point N lies on line q passing through point M, perpendicular to line p.
Points M and N are equidistant from line p.
It holds:
p∩q = S, MS = SN

two-lines-7

The desired point is N[3;0].

8. Write the equation of the angle bisector of the lines:

p: [3x – 4y – 2 = 0]
q: [5x – 12y + 26 = 0]
Solution:

The angle bisector of lines p and q is the line whose points are equidistant from both lines.

two-lines-8

There are two angle bisectors (perpendicular to each other):
o1: [7x + 4y - 78 = 0]
o2: [8x - 14y + 13 = 0]

9. Write the equation of the line q, which passes through the point M [1;3] and forms an angle φ = 45° with the line p: [2x – y + 5 = 0].

Solution:

dve-priamky-9

The desired lines are two:
q1: [x – 3y + 8 = 0]
q2: [3x + y – 6 = 0]

10. Three neighboring villages have the following locations on the map:

A[2;-1]
B[5;-2]
C[10;3]

Where will the common community center be located, which should be equidistant from all three villages?
Solution:

The location of the community center is determined as the intersection of the perpendicular bisectors of the sides of triangle ΔABC.

dve-priamky-10

The location of the community center will be at point S[5;3].

11. Find the set of all points in the plane that are equidistant from the parallel lines:

p: [2x – 3y + 10 = 0]
q: [4x – 6y + 5 = 0]
Solution:

dve-priamky-11

The desired set is the line o: [8x – 12y + 25 = 0].

12. On the line p: [5x – 4y - 28 = 0], determine the point that is equidistant from the points M [1;5] and N [7;-3].

Solution:

dve-priamky-12

13. Determine the coordinates of the center of square ABCD, if one vertex A[-3;-4] is given and the diagonal BD lies on the line p: [3x +4y – 25 = 0].

Task image
Solution:

dve-priamky-13

The coordinates of the center of square ABCD are S[3;4].

14. Determine the locus of points whose distances from the lines:

p: [3x + 4y - 23 = 0]
q: [12x – 5y – 13 = 0]
are in the ratio dp:dq = 2:3.
Solution:

dve-priamky-14

The loci of points are the lines 3x - 206y + 737 = 0 and 237x + 106y - 1027 = 0.