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Rigid body

1.What do we know about the properties of a rigid body?

Solution:

A rigid body is an ideal body whose shape and volume do not change under the action of external forces. External forces cause a change in the state of motion of the rigid body. The motion of the body can be:

mechanika-tuheho-telesa-1.gif


2.At the corners of a rectangular plate with sides a = 30 cm, b = 40 cm act forces F1 = 10 N, F2 = 20 N, F3 = 30 N, F4 = 40 N. The plate can rotate about an axis perpendicular to the plate passing through vertex A. What is the resultant moment of the forces acting on the plate?

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Solution:

mechanika-tuheho-telesa-2v.gif 

The resultant moment of the forces is 5 N·m.


3.A rectangular plate with dimensions a = 20 cm, b = 10 cm is mounted so that it can rotate about an axis passing through its center O perpendicular to the plate. Force F1 = 800 N. Calculate the magnitude of force F2 so that the plate remains at rest.


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Solution:

Analysis:

a = 20 cm = 0.2 m, b = 10 cm = 0.1 m, r1 = 0.1 m, r2 = 0.05 m, F1 = 800 N

 

mechanika-tuheho-telesa-3.gif 

For the plate to remain at rest, the force F2 must be 1600 N.


4.The rod has length 1.2 m. Weights of mass 5 kg and 7 kg are hung on its ends. Where should the rod be supported so that it remains in equilibrium?

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Solution:

Analysis:

r = 1.2 m, m1 = 5 kg, m2 = 7 kg, F1 = 50 N, F2 = 70 N

zad-4n r1 + r2 = r

F1·r1 = F2·r2

r1 + r2 = 1.2 ⇒ r2 = 1.2 − r1

50·r1 = 70·r2

50·r1 = 70·(1.2 − r1)

50 r1 = 84 − 70 r1

120 r1 = 84

r1 = 0.7 m, r2 = 0.5 m 

The rod should be supported at a distance of 0.7 meters from force F1.


5.On a rotating pulley, weights m1 = 0.5 kg at distance r1 = 0.2 m and m2 = 0.2 kg at distance r2 = 0.4 m from the axis of rotation are hung on the same side of the rotation axis. At what distance from the axis must we hang a weight m3 = 0.6 kg on the other side so that equilibrium occurs?

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Solution:

Analysis:

m1 = 0.5 kg, m2 = 0.2 kg, m3 = 0.6 kg, F1 = 5 N, F2 = 2 N, F3 = 6 N, r1 = 0.2 m, r2 = 0.4 m, x = ?

mechanika-tuheho-telesa-5.gif 

The counterweight must be attached at a distance x = 0.3 m from the axis of rotation.


6.How much work must we perform to spin a steel cylinder of mass 800 kg and base radius 0.5 m up to 48 revolutions per minute? Moment of inertia of a solid cylinder: (Tables)

Solution:

mechanika-tuheho-telesa-6.gif 

We must perform work W = 1262 J.


7.What is the moment of inertia of a flywheel if, during braking by work of 1260 J, its rotations drop from 320 min-1 to 254 min-1?

Solution:

mechanika-tuheho-telesa-7.gif 

The flywheel's moment of inertia is approximately I = 6.1 kg·m2.


8.A steel disc was spun using a rope of length 80 cm on which a force of 30 N acted. How many revolutions will it make in 1 second if its moment of inertia is 0.03 kg·m2?

Solution:

Analysis:

l = 80 cm = 0.8 m, F = 30 N, I = 0.03 kg·m2, f = ?

mechanika-tuheho-telesa-8.gif 

The steel disc makes 6.34 revolutions per second.


9.To what height would a toy car climb up a hill if it is driven only by a flywheel with moment of inertia 0.1 kg·m2? The flywheel makes 4 revolutions per second. The mass of the toy car is 8 kg.

Solution:

Analysis:

I = 0.1 kg·m2, f = 4 s-1, m = 8 kg, h = ?

 mechanika-tuheho-telesa-9.gif

The toy car will climb to a height h = 40 cm.


10.Determine the minimum frequency that a flywheel with moment of inertia 305 kg·m2 must reach so that over a time of 10 minutes it delivers power of 25 kW.

Solution:

Analysis:

I = 305 kg·m2, t = 10 min. = 600 s, P = 25 000 W, f = ?

mechanika-tuheho-telesa-10 

The minimum frequency of the flywheel is f = 50 s-1.


11.

Explain when we use Steiner's theorem (the parallel-axis theorem) in the calculation of the moment of inertia of a rigid body?

Solution:

If the axis of rotation of the rigid body does not pass through the center of mass, Steiner's theorem applies.

I = I0 + m·d2

I0 – moment of inertia of the body when the axis of rotation passes through the center of mass

m – mass of the body

d – distance of the center of mass from the axis of rotation

 

Moments of inertia of some bodies:

mechanika-tuheho-telesa-11.gif


12.Calculate the moment of inertia of a solid homogeneous sphere with radius r = 10 cm and mass 25 kg with respect to an axis that is tangent to the surface of the sphere.

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Solution:

Analysis:

r = 10 cm = 0.1 m, m = 25 kg, d = r = 0.1 m

mechanika-tuheho-telesa-12.gif 

The moment of inertia of the sphere is I = 0.35 kg·m2.


13. Determine the length of the rod l whose mass is 1.2 kg and modulus of inertia is 0.592 kg·m2, if the rod rotates at a distance 0.4 m from the fixed axis.

Solution:

Analysis:

m = 1.2 kg, I = 0.592 kg·m2, d = 0.4 m, l = ?

mechanika-tuheho-telesa-13.gif 

The length of the rod is l = 2 m.


14.A solid wheel (circular disc) of mass 20 kg and radius r = 50 cm rolls with speed 10 m·s-1. What is its kinetic energy?

Solution:

Analysis:

mechanika-tuheho-telesa-14-1.gif

Rolling motion is composed of translational and rotational motion. It holds: mechanika-tuheho-telesa-14-2.gif

mechanika-tuheho-telesa-14-3.gif

The kinetic energy of the wheel is Ek = 1.5 kJ.


15.

What speed does a sphere gain when it rolls down an inclined plane from a height of 1 m?

Solution:

Analysis:

mechanika-tuheho-telesa-15.gif 

The sphere attains a speed v = 3.78 m·s-1