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Dispersion and polarization of light


1. Explain the dispersion and polarization of light.

Solution:

Decomposition of Light

White light is a mixture of seven monochromatic colors (red, orange, yellow, green, blue, indigo, violet), i.e., a mixture of electromagnetic waves with different frequencies.

R   O      Y      G      B      I      V
f (10¹⁴ Hz)    4.6      5.0      5.2      5.75      6.7      7.0

Individual colored lights propagate in a medium at different speeds v<cv < c,
therefore they have different refractive indices and refract at different angles.

n=λ0λ=ccλf=cλfn = \frac{\lambda_0}{\lambda} = \frac{c}{\frac{c}{\lambda f}} = \frac{c}{\lambda f} v=cn=ccλf=λfv = \frac{c}{n} = \frac{c}{\frac{c}{\lambda f}} = \lambda f


Polarization of Light

Natural light is unpolarized. It is a transverse electromagnetic wave, characterized by oscillations of mutually perpendicular vectors
EB. On the retina of the eye, only the oscillations of the vector of electric field intensity E\vec{E} act.
In polarized light, the oscillation of vector E\vec{E} occurs in one plane.

Complete polarization occurs when the angle of incidence is the so-called Brewster’s angle αp\alpha_p.

tanαp=n2n1\tan \alpha_p = \frac{n_2}{n_1}

At the polarization angle αp\alpha_p, the reflected ray is perpendicular to the refracted ray.


2.The wavelength of the hydrogen line H2 in air is λ0 = 656.4nm. What is its wavelength in water? (n = 1.33)

Solution:

Analysis:

 fyzika-rozklad-a-polarizacia-svetla-2r.gif

The wavelength of the hydrogen line H2 in water is λ = 493.5nm.


3. Determine whether the speed at which light propagates depends on its frequency

a) in vacuum, n=1n = 1
b) in a medium, n=cfλn = \dfrac{c}{f \lambda}

Solution:

a) In vacuum:

n=cvn = \frac{c}{v}

v=cn=c1=cv = \frac{c}{n} = \frac{c}{1} = c

v=c does not depend on frequencyv = c \;-\; \text{does not depend on frequenc


b) In a medium:

n=cvn = \frac{c}{v}

v=cn=cfλ=fλv = \frac{c}{n} = \frac{c}{f\lambda} = f\lambda

v=fλ depends on frequencyv = f\lambda \;-\; \text{depends on frequenc 

In vacuum, the speed of light does not depend on frequency, in a medium it does.


4. Derive the formula for calculating Brewster's angle – the angle of complete polarization.

Solution:

At the polarization angle αp, the reflected beam is perpendicular to the refracted beam.
 
fyzika-rozklad-a-polarizacia-svetla-4.gif
The formula for calculating Brewster's angle is tgαp = n1,2


5. The angle of complete polarization for opaque enamel is αp = 58°. What is the refractive index of the enamel? (n1=1,n2=?)

Solution:

Analysis:

fyzika-rozklad-a-polarizacia-svetla-5.gif 

The refractive index of enamel is n2 = 1.6


6. Calculate Brewster's angle of complete polarization for:

  • water: n = 1.33
  • glass: n = 1.5
  • diamond: n = 2.465

Solution:

Water:       tanαp=n=1.33αp=53
Glass:        tanαp=n=1.5αp=56.3\tan \alpha_p = n = 1.5 \Rightarrow \alpha_p = 56.3^\circ
Diamond: tanαp=n=2.465αp=68\tan \alpha_p = n = 2.465 \Rightarrow \alpha_p = 68^\circ

Brewster's angle of complete polarization is for water 530, glass 56.30 and diamond 680.


7.Complete the table of light dispersion:

                                 R      O      Y       G        B        I        V
rozklad-a-polarizacia-svetla-7z

Solution:

rozklad-a-polarizacia-svetla-7r1

                   R         O          Y        G          B         I          V

rozklad-a-polarizacia-svetla-7r2


8.A light ray falls from air onto the water surface at an angle of incidence α = 70o. Determine which of the colored rays (red or violet) deviates the least or the most from the original direction of the light ray before striking the water.

Solution:

rozklad-a-polarizacia-svetla-8 

The red ray deviates the least from the original direction, the violet ray deviates the most.


9.A diamond plate (n = 2.465) is illuminated with the violet component of light (f = 7.8·1014 Hz). Determine the wavelength of the violet component of light in vacuum and in the diamond.

Solution:

rozklad-a-polarizacia-svetla-9 

The wavelength of the violet component of light in vacuum is λ0 = 3.84·10–7 m, and in the diamond λD = 1.55·10–7 m.


10.The angle of complete polarization for diamond is αP = 68o. What is the refractive index of diamond? At what angle does a monochromatic light ray refract if its angle of incidence is the angle of complete polarization?

Solution:

rozklad-a-polarizacia-svetla-10 

The refractive index of diamond is nD = 2.475. The angle of refraction is β = 22o.


11.At what angle of incidence does complete polarization occur when light is reflected at the interface of ice (n1 = 1.308) and water (n2 = 1.333)?

Solution:

rozklad-a-polarizacia-svetla-11 

Complete polarization occurs when the angle of incidence equals the polarization angle αP = 45.5o.